Question

Which is the distance between the point with the coordinates (-2, 3) and the line with the equation 6x-y=-3

Answer 1

The Answer is D. The person above me did not simplify completely

Explanation:

Answer 2

`(12)/(√(37))` units.

Explanation:

The perpendicular distance from a point (
`x_(1),y_(1)`) from a given straight line ax + by + c = 0 is given by the formula

`\frac{\sqrt{a^(2) + b^(2)}}`.

So, the distance from the point with coordinates (-2,3) to the straight line with equation 6x - y = - 3 i.e. 6x - y + 3 = 0 will be

`\frac6(-2) - 1(3) + 3{\sqrt{6^(2) + (- 1)^(2)}} = (12)/(√(37) )` units. (Answer)