Question

Two coils are placed close together in a physics lab to demonstrate Faraday’s law of induction. A current of 5.00 A in one is switched off in 1.00 ms, inducing a 9.00 V emf in the other. What is their mutual inductance?

Answer 1

Mutual inductance will be
`M=1.8* 10^(-3)Hennry`

Step-by-step explanation:

We have given induced current
`\Delta i=5A`

Time is given as
`t=1ms=10^(-3)sec`

We have to find the mutual inductance between the coils

Induced emf is given as e = 9 volt

We know that induced emf is given by

`e=M(\Delta i)/(\Delta t)`

`9=M* (5)/(10^(-3))`

`M=1.8* 10^(-3)Hennry`