Answer:
C) The area of the sector TSV = 1.1 sq m.
Explanation:
Here, the angle subtended by TSV at the center of the circle = 3 radians.
1 Radians = 57.2958°
So, 3 radians = 3 x 57.2958 = 171.887 °
⇒The angle of the sector TSV = 171.887 °
Now, the angle of any sector of a circle with angle Ф at the center
=
![(\theta)/(360) * \pi * (r^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/byzfy9t0bc4ubp9x7k7gmu1q1vl3siocx5.png)
Here, r = 0.87 m
So, the area of the sector TSV =
![(171.887)/(360) * (22)/(7) * (0.87)^2 = 1.1358](https://img.qammunity.org/2020/formulas/mathematics/middle-school/oe38digsd5hoh0nf1yjki7h0y4nmr2dbp1.png)
or, the area of the sector TSV = 1.13 sq m.
Now, rounding off the area to the nearest tenth ,we get:
The area of the sector TSV = 1.1 sq m.