Question

What is the equation of a line with a slope of ​ ​ −4 ​ ​ and a point ​ (−2, 5) ​ on the line? Express the equation in the form of y=mx+b where m is the slope and b is the y-intercept.

Answer 1

y= -4x-3

Explanation:

to find this, the first step is easy. We know the slope is -4 so we have y= -4x+b. Then we to find the y intersept, so we take the point that we have (-2,5) and make x (the first number) equal to 0. to do this we add two, which means to subtract 8 from give because the slope is -4. This gives the point (0,-3). So the equation is y= -4x-3.

Answer 2

y = - 4x - 3

Explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and c the y- intercept )

Here m = - 4, thus

y = - 4x + b ← is the partial equation

To find b substitute (- 2, 5) into the partial equation

5 = 8 + b ⇒ b = 5 - 8 = - 3

y = - 4x - 3 ← equation of line