Question

A power plant uses 365 GJ/hr of energy from a boiler and extracts 18 GJ/hr as work from a turbine and rejects the remaining energy to a large cold resevoir of air (the atmosphere). What is the rate of heat rejection to the atmosphere for this plant? Give your answer in GJ/hr

Answer 1

The rate of heat rejection will be 347 GJ/hr

Step-by-step explanation:

We have given that power plant uses energy of 365 GJ/hr

So energy uses
`Q_B=365GJ/hr`

Work done from turbine
`W_T=18GJ/hr`

We have to find the rate of heat rejection to the atmosphere
`Q_C`

We know that
`Q_B=W_T+Q_C`

`365=18+Q_C`

`Q_C=347GJ/hr`

So the rate of heat rejection will be 347 GJ/hr