Question

A neutral atom with the electron configuration 2-8-6 would most likely form a bond with an atom having the configuration

Answer 1

A neutral atom with the electron configuration 2-8-6 would most likely form a bond with an atom having the configuration 2-5, such as a neutral nitrogen atom.

Step-by-step explanation:

A neutral atom with the electron configuration 2-8-6 refers to an atom with 16 electrons. To determine the atom it would most likely form a bond with, we consider the octet rule which states that atoms are more stable when they have 8 electrons in their valence shell. Based on this rule, the atom with a configuration that would most likely form a bond with the given atom is an atom with 5 electrons in its valence shell, such as a neutral nitrogen atom with the electron configuration 2-5.

Answer 2

The configuration of the atom would be 2-8-2.

Step-by-step explanation:

Any atom of an element combines with other element to complete its octet and become stable.

The electron configuration of the given atom is 2-8-6. That means the atom has 6 electrons in its outermost shell. To become stable the atom should have 8 electrons in its outermost shell. The given atom has 6 electrons so it either lose 6 electrons or gain 2 electrons to complete its octet.

But we know the atom having 5,6,7 electrons in its outermost shell they do not lose, they gain either 3 or 2 or 1 electrons to complete its octet.

So we say that atom with the electron configuration 2-8-6 bond with the atom having electron configuration 2-8-2.