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Evaluate x(y+3)/(3+y)z for x=6 y=9 z=2

I'm struggling to solve this equation. Please help me. thank you!

User Deif
by
5.2k points

2 Answers

3 votes
I got 72/24 because I swapped out the variables with the numbers and continued with distributive property
Evaluate x(y+3)/(3+y)z for x=6 y=9 z=2 I'm struggling to solve this equation. Please-example-1
User Daxnitro
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5.4k points
4 votes

Answer:3

Step-by-step explanation:plug in the numbers in the algebraic expression. Should look like this: 6(9+3)/(3+9)2. After you set it up like this you have to get rid of the parentheses by multiplying the outside number to the numbers in the parentheses. So do: 6×9=54, then 6×3=18 so now your problem should look like this 54+18/ (3+9)2 do the same with the other side so: 2×3=6, then 9×2=18 now your problem should look like this: 54+18/6+18 now you add each side up 54+18=72 and 6+18=24 . Then divide those 2 answers which looks like this 72/24 = 3.

User Cy Bu
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5.2k points
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