165k views
3 votes
Serious answers only. Do not answer if you dont know please!How does the graph of the circle described by x^2 + (y-7)^2 = 49 change when its equation is changed to (x +5)^2 + (y-4)^2 =64. Select each correct answer. The circles radious increases, The circle moves up, The circle moves left, The circles radious decreases, The circle moves down, The circle movea right.

User Sircrisp
by
7.3k points

1 Answer

4 votes

Answer:

  • The circles radious increases
  • The circles moves left
  • The circles moves down

Explanation:

  • The equation of a circle can be written as
    (x-a)^2+(y-b)^2=r^2, where "r" is the radious, and (a,b) are the coordenates in the axis x and b respectively.
  • Then, in the first circle the coordenates are (0,7), which means that the circle will be center there, and the radious is 7 (
    √(49)).
  • The second circle have different coordenates: (-5,4), which means that the circle has moved left (from 0 to -7 in the x axis) and down (from 7 to 4 in the y axis). Additionally, its radious has increased from 7 (
    √(49), from 8 (
    √(64)).
  • See the attached figure please.
  • Then, the correct answers are:
  1. The circles radious increases (from r=7 to r=8)
  2. The circles moves left (from x=0 to x=-5)
  3. The circles moves down (from y=7 to y=4)
Serious answers only. Do not answer if you dont know please!How does the graph of-example-1
User Nicoy
by
7.8k points