Answer: A< B< D< C
Step-by-step explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
![pH=-\log [H^+]](https://img.qammunity.org/2020/formulas/chemistry/high-school/ipfjz05f4cfbguiwup37xvxa7furlbuapf.png)
![pOH=-\log[OH^-]](https://img.qammunity.org/2020/formulas/chemistry/high-school/n477c3o3xy8p6ug3ipfjqh9fd53hdrrjyq.png)
Lower is the
, higher is the acidity.
a. Solution A: pH = 8.46
Putting in the values:
![8.46=-\log [H^+]](https://img.qammunity.org/2020/formulas/chemistry/high-school/pbcsjczyicgaxihnqux7ij40vfnubmqeu2.png)
![[H^+]=3.47* 10^(-9)M](https://img.qammunity.org/2020/formulas/chemistry/high-school/hl3ccwh329crlwzx45vpisiqqgxlaurmu1.png)
b. Solution B: pOH = 9.30
![9.30=-\log [OH^-]](https://img.qammunity.org/2020/formulas/chemistry/high-school/mfcypz7vh5tpb09xx54sd3e0uebscht5ap.png)
![[OH^-]=5.01* 10^(-10)M](https://img.qammunity.org/2020/formulas/chemistry/high-school/w4bqo468ihz8dlz9bgqrspuo0iscia4ej9.png)
![[H^+][OH^-]=10^(-14)](https://img.qammunity.org/2020/formulas/chemistry/high-school/kygctthkoa5ws7izf8efhkrnwy3gl37uak.png)
![[H^+]=(10^(-14))/(5.01* 10^(-10))=0.20* 10^(-4)](https://img.qammunity.org/2020/formulas/chemistry/high-school/p0inxpwuugfhjb3usxlzf70pp6k9gxobjg.png)
c. Solution C:
![[H^+]=2.5* 10^(-4)](https://img.qammunity.org/2020/formulas/chemistry/high-school/a5o83ugniweng2d8f633yclig7i3uubrpe.png)
d. Solution D:
![[OH^-]=1.1* 10^(-10)](https://img.qammunity.org/2020/formulas/chemistry/high-school/zpe2jnyeox70i3i4jrv0zcw65do3lk2znw.png)
![[H^+][OH^-]=10^(-14)](https://img.qammunity.org/2020/formulas/chemistry/high-school/kygctthkoa5ws7izf8efhkrnwy3gl37uak.png)
![[H^+]=\frac{10^(-14)}[1.1* 10^(-10)}=0.91* 10^(-4)](https://img.qammunity.org/2020/formulas/chemistry/high-school/nen6g2yp266snhkq4v6ku6a30ofvc5274q.png)
Thus the order of increasing acidity is A< B< D< C