Question

Birdman is flying horizontally at a

speed of 35 m/s and a height of 79

m. Birdman releases a turd directly

above the start of the field. How far

from the start of the field should the

robot hold the bucket to catch the

turd?

Answer 1

311.5 m

Step-by-step explanation:

First let's calculate the time it takes for the turd to reach the ground.

`y = v_(i) t + (1)/(2) gt^(2) \\79 = 0*t +(1)/(2) *9.8*t^(2) \\t = 8.9 s`

With no air resistance, the horizontal component of velocity does not change.

So the horizontal distance will be = 35 m/s * 8.9 s = 311.5 m