Question

Metal-X = Molybdenum

Metal-Y = Iron



Metal-X forms a substitutional solid solution with Metal-Y. Compute the number of Metal-X atoms per cubic centimetier for a Metal-Y---Metal-X alloy that contains 33wt% Metal-X and 67 wt% Metal-Y.

Answer 1

there are two Mo atoms per seven Fe atoms

Step-by-step explanation:

The metal X = Molybdenum

Metal Y = Iron

The atomic weight of

Mo = 96 g/ mol

Fe = 56 g/mol

The weight ratio of given metals is

Mo = 33%

Fe =67%

Let us calculate the moles of each metal in 100g of sample.

`mole=(mass)/(atomicmass)`

`Mole(Mo)=(33)/(96)= 0.34`

`mole(Fe)=(67)/(56)=1.2`

Thus metal atom ratio =
`0.34:1.2 = 2:7`

Thus there are two Mo atoms per seven Fe atoms