Answer:
Explanation:
Given that a study found that the average stopping distance of a school bus traveling 50 mph was 264 feet.
Sample taken showed the following results
![n=40\\\bar x =262.3 feet\\Std dev = \sigma= 3 ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/mv9b5ii5kbt7br9zd8e2qjlyxb8dpp5lc7.png)
Since population std deviation is known and sample size is large, z test can be used.
![H_0: \bar x=264\\H_a: \bar x <264](https://img.qammunity.org/2020/formulas/mathematics/high-school/8wcfckdmxrm1qtub3fby6dpf6xxnjsxexu.png)
(Left tailed test)
Mean difference =
![264-262.3 = 1.7](https://img.qammunity.org/2020/formulas/mathematics/high-school/3hr3eo9r7x68ejabenv8y37vvnzs72plgi.png)
Std error =
![(\sigma)/(√(n) ) \\=(3)/(√(40) ) \\=0.474](https://img.qammunity.org/2020/formulas/mathematics/high-school/qj2zi8gsyoecjb3b2gjiu0on4xm4lhylgi.png)
Z = test statistic = mean diff/std error
=
![(1.7)/(0.474) \\=3.584](https://img.qammunity.org/2020/formulas/mathematics/high-school/x8kmqoew2tuxtxcqf6phfeapj45ql2h81v.png)
p value = 0.00017
Since p < alpha our 0.05 we reject null hypothesis
There is evidence to show that mean is less than 264 feet
(Assumptions:
Sample are randomly drawn
Sample represents the population