Question

Consider the following reaction: 4Fe + 302 → 2Fe2O3. What mass of iron(III) oxide would

be produced if 250 g of Fe were reacted with 120 g of oxygen?

Answer 1

Mass = 357.7 g

Step-by-step explanation:

Given data:

Mass of Fe = 250 g

Mass of oxygen = 120 g

Mass of iron(III) oxide produced = ?

Solution:

Chemical equation:

4Fe + 3O₂ → 2Fe₂O₃

Number of moles of Fe:

Number of moles = mass/molar mass

Number of moles = 250 g/ 55.8 g/mol

Number of moles = 4.48 mol

Number of moles of O₂ :

Number of moles = mass/molar mass

Number of moles = 120 g/ 32 g/mol

Number of moles = 3.75 mol

Now we will compare the moles of reactants with product.

Fe : Fe₂O₃

4 : 2

4.48 : 2/4×4.48 = 2.24

O₂ : Fe₂O₃

3 : 2

3.75 : 2/3×3.75= 2.5

Less number of moles of Fe₂O₃ are produced by Fe thus it will act as limiting reactant.

Mass of Fe₂O₃:

Mass = number of moles × molar mass

Mass = 2.24 mol × 159.69 g/mol

Mass = 357.7 g