Answer:
![22\ units^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/38g3z4e5glgtjkhdwd5csmabgpdb3hvs1s.png)
Explanation:
we know that
The area of the figure is equal to the area of a triangle plus the area of a parallelogram
Find the area of triangle KLM
![A=(1)/(2) (b)(h)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/syyy1my8cl5toxsmezmnm0af1r9cluwlq6.png)
we have
--> difference of the x-coordinates points M and K
--> difference of the y-coordinates points L and K
substitute
![A_1=(1)/(2) (4)(3)=6\ units^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6zwuog5u9xadvmu6pxyxrdztlftbaa2c5h.png)
Find the area of parallelogram JKMN
![A=(B)(H)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mjrnlpbm330j92itaxnv1mbaifiwfzqtk5.png)
--> difference of the x-coordinates points N and J
--> difference of the y-coordinates points K and J
substitute
![A_2=(4)(4)=16\ units^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z3m517h7l2z0vvp8tg12fony2cepwfg6da.png)
The area of the figure is equal to
![A=A_1+A_2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/oju05fe8l4a9pdeaqxdducmrqthifbndmi.png)
![A=6+16=22\ units^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8f9vxmqay9kjhszv0klhaolmo89gtfsah0.png)