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A ship sails 30.50 mi due East and then turns 33.75 north of East. After sailing another 18.53 mi, where is it with reference to the starting point

User Miri
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A ship sails 30.50 mi due East and then turns 33.75 degree north of East. After sailing another 18.53 mi, where is it with reference to the starting point

Answer:

The ship is 18.269 miles distance north of east from starting point

Solution:

Given that ship sails 30.50 miles east

North of east = 18.53 miles

Angle between two sides = 33.75 degree

The figure is attached below

In the figure, A represents starting point

AB = c represents the ship distance with reference to starting point

By using law of cosines,


c^(2)=a^(2)+b^(2)-2 a b \cos c


c^(2)=(30.50)^(2)+(18.53)^(2)-2(30.50)(18.53) \cos 33.75


c^(2)=930.259+343.3609-939.835


\begin{aligned} c^(2) &=333.7849 \\\\ c &=\pm 18.269 \end{aligned}

Ignore negative value as we measure distance in positive

c = 18.269

It is 18.269 miles distance north of east from starting point

A ship sails 30.50 mi due East and then turns 33.75 north of East. After sailing another-example-1
User Grynets
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