A ship sails 30.50 mi due East and then turns 33.75 degree north of East. After sailing another 18.53 mi, where is it with reference to the starting point
Answer:
The ship is 18.269 miles distance north of east from starting point
Solution:
Given that ship sails 30.50 miles east
North of east = 18.53 miles
Angle between two sides = 33.75 degree
The figure is attached below
In the figure, A represents starting point
AB = c represents the ship distance with reference to starting point
By using law of cosines,




Ignore negative value as we measure distance in positive
c = 18.269
It is 18.269 miles distance north of east from starting point