Answer:
Initial velocity 192.666 ft/sec
a) 1.41 sec
Explanation:
Equations for
V(f) = V₀ ± at
V(f)² =( V₀)² ± 2 a*d
d = V₀*t ± a*t²/2
We are going to use a(t) = g = 32 ft/sec²
a) V₀ = ?? a = -g
Then as d = 580 ft and V(f) = 0
we have
V(f)² = ( V₀)² - 2*32*580 ⇒ ( V₀)² = 64*580 (ft²/sec²)
( V₀)² = 37120 V₀ = 192,666 ft/sec
a) t = ?? in this case V₀ = 0
d = V₀*t + gt²/2 ⇒ 32 = ( 32 t²) /2
t² = 2
t = 1.41 sec