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Find the value of
a.) lim (x²-1)/(x²+1)
x−>∞


User Labu
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1 Answer

5 votes

Answer:


\displaystyle\lim_(x \to \infty) (x^2-1)/(x^2+1) \\ \text{take $x^2$ common from numerator and denominator} \\ \displaystyle\lim_(x \to \infty) (1-(1)/(x^2))/(1+(1)/(x^2)) \\</p><p></p><p></p><p>\text{Now put the limit}</p><p>\\</p><p>\displaystyle\lim_(x \to \infty) (1-0)/(1+0)= 1</p><p>

User Susaj S N
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