73.2k views
4 votes
Find the values of x in this equation: x-15/x=2

2 Answers

1 vote

Answer:

E.

-3, 5

Explanation:

User Aadi
by
4.6k points
1 vote

Answer:

The values of x are -3 and 5

Explanation:

we have


x-(15)/(x)=2

Multiply by x both sides to remove the fraction


x^(2) -15=2x\\\\x^(2) -2x-15=0

The formula to solve a quadratic equation of the form


ax^(2) +bx+c=0

is equal to


x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}

in this problem we have


x^(2) -2x-15=0

so


a=1\\b=-2\\c=-15

substitute in the formula


x=\frac{-(-2)(+/-)\sqrt{-2^(2)-4(1)(-15)}} {2(1)}


x=\frac{2(+/-)√(64)} {2}


x=\frac{2(+/-)8} {2}


x_1=\frac{2(+)8} {2}=5


x_2=\frac{2(-)8} {2}=-3

therefore

The values of x are -3 and 5

User Smishra
by
4.9k points