Question

A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32° ramp, measured from the horizontal, at a speed of 40.0 m/s (144 km/h). The top of the ramp is at the same height as the roofs of the buses and each bus is 20.0 m long.

Answer 1

The number of buses are 7.

Step-by-step explanation:

Given that,

Angle =32°

Speed = 40.0 m/s

Length of bus = 20.0

We need to calculate the range of bus

Using formula of range

`R=(v^2\sin2\theta)/(g)`

Where, g = acceleration due to gravity

v = initial velocity

Put the value into the formula

`R=((40.0)^2*\sin(2*32))/(9.8)`

`R=150.20\ m`

We need to calculate the number of buses

Using formula of number of buses

`N=(R)/(L)`

Where, R = range

L = length of bus

`N=(150.20)/(20.0)`

`N=7`

Hence, The number of buses are 7.

Answer 2

Dare devil can cross 7 buses.

Step-by-step explanation:

given,

angle of inclination of ramp = 32°

speed of the motorcycle = 40 m/s

length of bus = 20 m

how many buses daredevil can clear =?

to solve this we need to calculate the range of the daredevil

considering it as projectile

the range of motorcyclist

`R = (V^2 sin (2\theta))/(g)`

`R = (40^2 sin (2* 32^0))/(9.8)`

`R =163.26 * sin(2* 32^0)`

`R =146.74\ m`

length of bus is given as 20 m

Number of bus daredevil can cross

`N = (147.74)/(20)`

`N =7.34`

Dare devil can cross 7 buses.