Question

Typically, when a person coughs, he or she first inhales about 2.20 L of air at 1.00 atm and 25 ∘ C . The epiglottis and the vocal cords then shut, trapping the air in the lungs, where it is warmed to 37 ∘ C and compressed to a volume of about 1.70 L by the action of the diaphragm and chest muscles. The sudden opening of the epiglottis and vocal cords releases this air explosively. Just prior to this release, what is the approximate pressure of the gas inside the lungs?

Answer 1

pressure of the gas inside the lungs will be =1.35 atm

Step-by-step explanation:

so for calculation of pressure of gas we will use the formula

(remember to convert *C to kelvin)

PV₁/T₁ = P₂V₂/T₂ As we know that Temperature = 310.5 k =37 degree

so for pressure P₂

P₂=P₁V₁T₂/T₁V₂

= ((1.00atm)(2.20L)(310.15K))/ ((298.15K) (1.70L)

=1.35 atm

(remember to convert *C to kelvin)