Question

A golf ball, thrown upwards, rises at a speed of v metres per second.

The ball reaches a maximum height of h metres.
h is proportional to the square of v.
When v = 20, h = 8
Work out the maximum height reached by the golf ball when v = 35

Answer 1

Answer:24.5

Explanation:

Formula:

H=KV²

8=K×20²(400)

=8/400

=0.02

H=0.02×35²

=24.5

Answer 2

The maximum height reached by the golf ball when v = 35 is 24.5 meters.

Explanation:

Given : A golf ball, thrown upwards, rises at a speed of v metres per second. The ball reaches a maximum height of h metres. h is proportional to the square of v. When v = 20, h = 8.

To find : Work out the maximum height reached by the golf ball when v = 35 ?

Solution :

h is proportional to the square of v i.e.
`h\propto v^2`

`h=kv^2`

Where, k is the constant of proportionality

When v = 20, h = 8,

`8=k(20)^2`

`8=400k`

`k=(8)/(400)`

`k=0.02`

The equation became
`h=0.02v^2`.

Now, when v = 35 the value of h is

`h=0.02(35)^2`

`h=0.02* 1225`

`h=24.5`

Therefore, the maximum height reached by the golf ball when v = 35 is 24.5 meters.