Question

For each sequence,find the first 4 terms and the 10th term
a) n+5
b)2n-1

Answer 1

a)6,7,8,9 and 10th term is 15.

b)1,3,5,7 and 10th term is 19.

Explanation:

Given a) n+5

b)2n-1

Solution for a) n+5

Taking the value of n is 1 we get the first term of the sequence;

`n+5=1+5=6`

Similarly taking the value of n 2,3,4 we get;

`2+5=7\\3+5=8\\4+5=9`

And for 10th term we take the value of n is 10 and get;

`n+5=10+5=15`

So the solution for 1st sequence is 6,7,8,9 and 10th term is 15.

Solution for b)2n-1

Taking the value of n is 1 we get the first term of the sequence;

`2n-1=2*1-1=2-1=1`

Similarly taking the value of n 2,3,4 we get;

`2n-1=2*2-1=4-1=3\\2*3-1=6-1=5\\2*4-1=8-1=7`

And for 10th term we take the value of n is 10 and get;

`2n-1=2*10-1=20-1=19`

So the solution for 2nd sequence is 1,3,5,7 and 10th term is 19.