Question

A horizontal rod 0.300 m long carries a current through a uniform horizontal magnetic field of magnitude 6.40×10−2 T that points perpendicular to the rod. Part A If the magnetic force on this rod is measured to be 0.140 N , what is the current flowing through the rod?

Answer 1

Current, 7.29 A

Step-by-step explanation:

It is given that,

Length of the horizontal rod, L = 0.3 m

Magnetic field through a horizontal rod,
`B=6.4* 10^(-2)\ T`

The magnetic force acting on the rod, F = 0.14 N

Let the current flowing through the rod is given by I. The magnetic force acting on an object in the uniform magnetic field is given by :

`F=ILB\ sin\theta`

Here,
`\theta=90^(\circ)`

`F=ILB`

`I=(F)/(LB)`

`I=(0.14\ N)/(0.3\ m* 6.4* 10^(-2)\ T)`

I = 7.29 A

So, the current flowing through the rod 7.29 A.