Answer:
24 boxes
Explanation:
The processor knows that the standard deviation of box weight is 0.5 pound

We are supposed to find How many boxes must the processor sample to be 95% confident that the estimate of the population mean is within 0.2 pound
Formula of Error=

Since we are given that The estimate of the population mean is within 0.2 pound
So,

z at 95% confidence level is 1.96





Hence the processor must sample 24 boxes to be 95% confident that the estimate of the population mean is within 0.2 pound