Answer:
4200
Explanation:
In an arithmetic sequence equation t=a + (n-1)d, a is the starting value. In this case, a=3000.
Although, since the initial investment is not considered the first month, the equation is t = a + dn.
d is the rate of change. In this case, the rate of change is 100 for every month, n.
Substitute these values from the problem to get an equation:
t = 3000 + 100n
t means the total amount of money we have for the amount of months (n) that passed.
Sub n for 12.
t = 3000 + 100n
t = 3000 + 100(12)
t = 4200
You will have $4200 after 12 months of investment.