Answer:
The graph is shown below.
Explanation:
Given:
Slope of the line is,
![m=-(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gzkjqcgnz8ew7y8ddbt3ilmy18cglvo4xd.png)
A point on the line is (-2,2).
Let us find the equation of a line using the point-slope form:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lwv5ftdd36i4idvu50qxfdgwxhdby4wlt5.png)
Here,
![x_1=-2,y_1=2,m=-(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dfuspa0rqlmkfuh63zabgt5pm1egkop09g.png)
![y-2=-(2)/(3)(x-(-2))\\y-2=-(2)/(3)(x+2)\\3(y-2)=-2(x+2)\\3y-6=-2x-4\\2x+3y=-4+6\\2x+3y=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jqq6uouyjk1werd079tqhatyz5jd89qqi0.png)
Let
, then
. So, a point is (1,0).
Another point is given as (-2,2)
Now, draw a line passing through these two points. This is the graph of the required line.