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Find parametric equations for the line. (use the parameter t.) the line of intersection of the planes x y z = 6 and x z = 0

User Ballenf
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1 Answer

17 votes
17 votes

Let
x=t. Then


x+z = 0 \implies z = -x = -t


x + y + z = 6 \implies y = 6 - x - z = 6 - t - (-t) = 6

so our parametric equations for the line are


\begin{cases}x(t) = t \\ y(t) = 6 \\ z(t) = -t\end{cases}

where
t\in\Bbb R.

User BillyTom
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