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Zeros of function y=x^2-3x-18

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substitute 0 for y and then solve for x

0=x^2-3x-18

x^2-3x-18
factor
(x-6)(x+3)
so set each factor equal to 0
x-6=0
x=6
x+3=0
x=-3

so the zeroes are -3,6
User Telson Alva
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