Answer:
The coordinates of the point M(x,y) = (3, -4)
Explanation:
The coordinates of the point A and B are A(1,4) and B(4,-8).
Let us assume the point which is 2/3 way on AB is m (x,y)
⇒ AM : AB = 2 : 3, So, AM = 2 parts of total 3 parts.
⇒ AM: MB = 2 : 1 (as M is 2 - 3rd )
Now, using Section Formula:
Coordinates for point (x,y) which vides the line (a,b) and (c,d) in m1: m2 is given as
![(x,y) = ((am2 + cm1)/(m1+m2) ,(dm1 + m2b)/(m1+m2) )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kasduhfnrpkyj6he269d5v6rkk5oj0w7pt.png)
Applying this here on A(1,4) and B(4,-8) with m1: m2 = 2: 1
![(x,y) = ((1(1) + 2(4))/(2+1) ,(-8(2)+ 4(1))/(2+1) ) = ((1+8)/(3), (-16+4)/(3) )\\\implies (x,y) = ((9)/(3) ,(-12)/(3) )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v4y0th3mw0r0kj41hj2ebmta3f7uj7xlyt.png)
or, (x,y) = (3,-4)
Hence the coordinates of the point M(x,y) = (3, -4)