Answer:
Length of the training track running around the field
![=524.38\ meters](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hp54xvvx1fh47uywm6orw4wcl68teivpau.png)
Explanation:
Length of the training track = Outer boundary measures Or Circumference of the field.
We have a rectangular enclosure and circumference/perimeter of a rectangle
![=2(length+Width)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/661u3mh7upvlkd5oeteychsflt305nktiu.png)
And we have
semicircle of same measures,
semicircles of same measure can be considered as a full circle.
So circumference of a circle
where
is the radius and
is the diameter.
And we see we have already being given the values of length ,width but nowhere it has mentioned the diameter.
But from the figure if we look upon,the width of the rectangle is the diameter of the semicircle,so diameter of the circle which is
![(d) = 67\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uq9pdlu4rqlkeplw8zkyj3222be9ytpgv0.png)
Finally the training track length = Perimeter of rectangle + Circumference of the circle,which
![=2(length+width) + \pi (diameter)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5wbvniqfnagc9js0c2n8bu64fkd9zrsmu1.png)
![=2(90+67) +3.14(67)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u93ehdi9xpu0rvbnlnsozuop5ubzgxmaqd.png)
![=(314+210.38) = 524.38\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mknhazqdttfwdwdaikb7mr600uzqc0pyev.png)
So the length of the training track
in meters.
The units are in meters.