Question

Find the area of a triangle with sides of length 5 and 6 and included angle 74 degrees

Answer 1

`A=14.42\ units^2`

Explanation:

we know that

The area of a triangle applying the law of sines is equal to

`A=(1)/(2)(a)(b)sin (C)`

where

C is the included angle between sides a and b

a and b are length sides of triangle

we have

`a=5\ units\\b=6\ units\\C=74\°`

substitute

`A=(1)/(2)(5)(6)sin (74\°)`

`A=14.42\ units^2`