Question

A car traveling along a straight road at 71 ft/sec accelerated to a speed of 79 ft/sec over a distance of 160 ft. What was the acceleration of the car, assuming it was constant? (Round your answer to two decimal places.)

Answer 1

Acceleration of car = 3.75 ft/s²

Step-by-step explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 71 ft/s

Final velocity, v = 79 ft/s

Displacement, s = 160 ft

Acceleration, a = ?

Substituting

v² = u² + 2as

79² = 71² + 2 x a x 160

a = 3.75 ft/s²

Acceleration of car = 3.75 ft/s²