Question

What is the oxidation number change for the manganese atom in the following unbalanced reduction half reaction: MnO4 -(aq) + H+(aq) → Mn2+(aq) + H2O(l)? Mn goes from +4 to +2 Mn goes from +3 to +2 Mn goes from +7 to +2 Mn goes from +8 to +2

Answer 1

The correct answer is Mn goes from +7 to +2.

Step-by-step explanation:

The permanganate ion (Mn04-) forming by Oxygen (-2 its oxidation state) and the Mn (+7), throwing the count: +7 + (-2 x4) = -1 (the charge of the ion). Said permanganate ion is reduced in the reaction to Mn2 +.