Question

What is the standard form of y+4=1/3(x+1)

Answer 1

`\displaystyle \boxed{x - 3y = 11}`

Explanation:

y + 4 = ⅓(x + 1)

y + 4 = ⅓x + ⅓

- 4 - 4

__________

y = ⅓x - 3⅔

- ⅓x - ⅓x

________

−⅓x + y = −3⅔ [We do not want mixed numbers\fractions in our standard equation, so multiply by the denominator to get rid of it.]

−3[−⅓x + y = −3⅔]

`\displaystyle x - 3y = 11`

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