Question

PLEASE HELP ASAP AND PLEASE SHOW ME THE WORK YOU DID TOO I NEED THISSS

Jeff and Gail are going to the Ranger station. Gail takes a short cut, which is 14.9 m, and Jeff goes the long way. He starts out walking east for 5.3 m, and then turns north. How far north will Jeff have to walk to meet Gail at the Ranger station? How much further will Jeff have to walk than Gail?

Answer 1

Jeff has to walk 13.9 m north.

Jeff has to walk 14.3 m futher than Gail.

Explanation:

Gail takes a short cut, which is 14.9 m, so Gail moves by the hypotenuse.

Jeff goes the long way. He starts out walking east for 5.3 m, and then turns north, so Jeff mowes by two legs. Let x m be the distance Jeff goes north.

By the Pythagorean theorem,

`14.9^2=5.3^2+x^2\\ \\x^2=14.9^2-5.3^2\\ \\x^2=193.92\\ \\x=13.9\ m`

So, Jeff has to walk 13.9 m north. In total, the long way is

`5.3\ m +13.9\ m=19.2\ m`

Jeff has to walk

`19.2\ m-14.9\ m=4.3\ m`

futher than Gail.