Question

A golfer hits a ball at an angle of 12 degrees above horizontal. The velocity of the ball is 37 m/s. What is the horizontal distance the ball travels in 2 seconds? A. 9.6 m B. 36 m C. 72 m D. 74 m

Answer 1

72 m is the horizontal distance the ball travels in 2 seconds.

Answer: Option C

Step-by-step explanation:

Velocity is defined as the distance travelled per unit time and expressed in m/s. The mathematical expression can be given as follows,

`\text {velocity}=(d i s t a n c e)/(t i m e)`

Now, the given datas are,

Angle made with the horizontal= 12 degrees

Velocity with which the ball was hit= 37 m/s

Time travelled= 2 s

The range ‘x’ of the horizontal component’s velocity can be calculated by,

`\text { Horizontal distance travelled }=\text { Horizontal velocity } * \text { Time }`

`x=v_(x 0) * t`

So, horizontal component of velocity,

`v_(x 0)=v \cos \theta=37 * \cos 12=37 * 0.978=36.186 \mathrm{m} / \mathrm{s}`

Now, horizontal distance travelled can be measured as,

`x = 36.186 * 2 = 72.372 m`

The value gets rounded off and the horizontal travelled distance as 72 m.