Question

Admission to a baseball game is $4.50 for general admission and $6.50

$6.50 for reserved seats. The receipts were $5008.50 for 945
paid admissions. How many of each ticket were sold? (Round to nearest integer if necessary.)

Answer 1

general admission tickets = 567

reserved tickets = 378

Explanation:

Let number of general admission tickets be "g"

and number of reserved seats be "r"

Total 945 tickets, that means:

g + r = 945

Also, total value of all tickets is 5008.5, so we can write:

4.5g + 6.5r = 5008.5

We can write 1st equation as:

g = 945 - r

Now we plug it into 2nd equation and solve for r first:

`4.5g + 6.5r = 5008.5\\4.5(945-r) + 6.5r = 5008.5\\4252.5-4.5r+6.5r=5008.5\\2r=756\\r=378`

Now, g is equal to:

g = 945 - r

g = 945 - 378

g= 567

So, reserved tickets sold were 378

and

general admission tickets sold were 567