Question

An IRS auditor selects 3 tax returns from 59 returns of which 7 contain in errors. Find the probability that she selcects none of those containing erros

Answer 1

4 containing errors

Step-by-step explanation:

Answer 2

The probability that she selects none of those containing errors is 0.68

Step-by-step explanation:

We are given that 7 out of 59 tax returns contain errors and an IRS auditor selects 3 tax returns from 59, we have to find the probability of selecting error free returns.

The probability is given by =
`\frac{\text {selection of error free tax returns}}{\text {selection of } 3 \text { random tox returns}}`

=
`(52 C 3)/(59 C 3)`

=
`(52 !)/(3 ! 49 !) / (59 !)/(3 ! 56 !)`

=0.68

Which is the required probability.