Answer:
The reaction is spontaneous for T>1099.3 K
Step-by-step explanation:
According to the Gibbs free energy (ΔG), a reaction is spontaneous when ΔG < 0. Because ΔG = ΔH - TΔS, the reaction is spontaneous when
ΔH - TΔS < 0
The standards values for enthalpy of formatio (ΔH°f) and entropy (ΔS) can be get by a thermodynamic table, which are:
MgSO₃(s): H° = -1068 kJ/mol; S° = 121 J/K.mol
MgO(s): H° = -601.7 kJ/mol; S° = 26.94 J/K.mol
SO₂(g): H° = -296.83 kJ/mol; S° = 248.22 J/K.mol
ΔH = ∑n*Hproducts - ∑n*Hreactant (n is the number of moles)
ΔH = (-601.7 - 296.83) - (-1068) = 169.47 kJ
ΔS = ∑n*Sproducts - ∑n*Sreactant
ΔS = (26.94 + 248.22) - (121) = 154.16 J/K = 0.1542 kJ/K
ΔH - TΔS < 0
169.47 - T*0.1542 < 0
-0.1542*T < - 169.47 (x-1)
0.1542T > 169.47
T > 1099.3 K
So, the reaction is spontaneous for T>1099.3 K