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You can now sell 40 cups of lemonade per week at 40¢ per cup, but demand is dropping at a rate of 1 cups per week each week. Assuming that raising the price does not affect demand, how fast do you have to raise your price if you want to keep your weekly revenue constant? HINT [Revenue = Price × Quantity.]

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Final answer:

To keep weekly revenue constant as the demand for lemonade drops by 1 cup each week, raise the price by approximately 0.41 cents per cup each week. Initially, 40 cups are sold at 40 cents each, yielding $16 in weekly revenue. The calculation involves solving for the price increase needed to offset the decrease in quantity sold.

Step-by-step explanation:

To keep weekly revenue constant while demand is dropping, you first need to understand the initial revenue. Currently, you sell 40 cups at 40¢ each, which totals to $16 (40 cups × $0.40/cup). To maintain this weekly revenue of $16, you have to compensate for each cup lost in demand by increasing the price per cup accordingly.

Let's denote the number of cups sold per week as Q and the price per cup as P. Since demand falls by 1 cup each week and revenue R is constant, the equation R = P × Q implies that the rate of change of the price, dP/dt, must adjust so that dR/dt = d(P × Q)/dt = 0. Assume demand drops to 39 cups in the next week. Then, to find out by how much to increase the price, set up and solve the equation: 16 = (40¢ + dP) × (40 cups - 1 cup).

Adding 1 cent to the price per cup will result in $15.60 in revenue (39 cups × 41¢) rather than the required $16. So, you need to increase the price by more than 1 cent per cup. Solving the equation, dP = 16/39 - 40¢.

Therefore, you have to raise the price by 0.410256 cents (or approximately 0.41 cents) per cup each week to maintain the revenue of $16 as demand falls by 1 cup each week.

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