Answer:
The required probability is 0.1667
Explanation:
Consider the provided information.
According to Probability Density Function:

Therefore,

The probability that such errors will be between –0.002 and 0.003 is:

![P(-0.002\leq x\leq 0.003)=(1)/(0.030)[x]^(0.003)_(-0.002)](https://img.qammunity.org/2020/formulas/mathematics/college/fllgm805asrwjw57k8evme217fw2wsyomx.png)

Hence, the required probability is 0.1667