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Abram and Fred leave opposite ends of a bike trail 8.5 miles apart and travel toward each other. Abram is traveling faster than Fred. Find each of their speeds if they meet after 30 minutes.

1 Answer

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Complete question :

Abram and Fred leave opposite ends of a bike trail 8.5 miles apart and travel toward each other. Abram is traveling 3mph faster than Fred. Find each of their speeds if they meet after 30 minutes.

Answer:

Fred's speed = 7mph

Abrams speed = 7 + 3 = 10 mph

Explanation:

Given that :

Distance apart = 8.5 miles

Let :

Fred's speed = x

Abram's speed = x + 3

Time they meet = 30 minutes = 0.5 hour

Speed = distance / time

Distance = speed * time.

Fred's distance + Abram's distance = 8.5 miles

(x * 0.5) + (x + 3)*0.5 = 8.5

0.5x + 0.5x + 1.5 = 8.5

x + 1.5 = 8.5

x = 8.5 - 1.5

x = 7 mph

Fred's speed = 7mph

Abrams speed = 7 + 3 = 10 mph

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