Question

A mover pushes a large crate (m = 75 kg) from the inside of the truck to the back end, which is a distance of 6 m. The mover exerts a steady push of 300 N. If he moves the crate this distance in 20 s, what is his power output during this time?

Answer 1

90 watts

Step-by-step explanation:

The power is given by:

`P=(Work)/(time)`

so we need to calculate the work done by the mover, that is given by:

`W=F*d*cos(\theta)`

the movement is parallel to the ground, so the angle is 0

`W=300N*6m*cos(0)\\W=1800J`

so the power is:

`P=(1800J)/(20s)=90W`