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Complete and balance the chemical equations for the precipitation reactions, if any, between the following pairs of reactants, and write the net ionic equations: a. Pb(NO3)2(aq) + Na2SO4(aq) → b. NiCl2(aq) + NH4NO3(aq) → c. FeCl2(aq) + Na2S(aq) → d. MgSO4(aq) + BaCl2(aq) →

User Karlos
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Step-by-step explanation:

a.
Pb(NO_3)_2(aq) + Na_2SO_4(aq) → ?


Pb(NO_3)_2(aq) + Na_2SO_4(aq)\rightarrow PbSO_4(s)+2NaNO_3(aq)


Pb(NO_3)_2(aq)\rightarrow Pb^(2+)(aq)+2NO_3^(-)(aq)


Na_2SO_4(aq)\rightarrow 2Na^++SO_4^(2-)(aq)


Pb^(2+)(aq)+2NO_3^(-)(aq)+2Na^++SO_4^(2-)(aq)\rightarrow PbSO_4(s)+2Na^++2NO_3^(-)(aq)

Removing common ions from both sides, we get the net ionic equation:


Pb^(2+)(aq)+SO_4^(2-)(aq)\rightarrow PbSO_4(s)

b.
NiCl_2(aq) + NH_4NO_3(aq)


NiCl_2(aq) + NH4NO_3(aq) \rightarrow Ni(NO_3)_2+NH_4Cl(aq)

No precipitation is occuring.

c.
Fe_Cl2(aq) + Na_2S(aq)


FeCl_2(aq) + Na_2S(aq)\rightarrow FeS(s)+2NaCl(aq)


FeCl_2(aq)\rightarrow Fe^(2+)(aq)+2Cl^(-)(aq)


Na_2S(aq)\rightarrow 2Na^++S{2-}(aq)


Fe^(2+)(aq)+2Cl^(-)(aq)+2Na^++S^(2-)(aq)\rightarrow FeS(s)+2Na^++2Cl^(-)(aq)

Removing common ions from both sides, we get the net ionic equation:


Fe^(2+)(aq)+S^(2-)(aq)\rightarrow FeS(s)

d.
MgSO_4(aq) + BaCl_2(aq)


MgSO4(aq) + BaCl2(aq)\rightarrow BaSO_4(s)+MgCl_2


MgSO_4(aq)\rightarrow Mg^(2+)(aq)+SO_4^(2-)(aq)


BaCl_2(aq)\rightarrow Ba^(2+)+2Cl^(-)(aq)


Mg^(2+)(aq)+SO_4^(2-)(aq)+Ba^(2+)+2Cl^(-)(aq)(aq)\rightarrow BaSO_4(s)+Mg^(2+)(aq)+2Cl^(-)(aq)

Removing common ions from both sides, we get the net ionic equation:


Ba^(2+)(aq)+SO_4^(2-)(aq)\rightarrow BaSO_4(s)

User Manas Khandelwal
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