Question

A car drove 330 miles in 6 hours at a constant rate. If the car’s rate of travel slows by 10 mph, what is the new, slower rate of travel?

Answer 1

45 mph

Explanation:

Given: Distance travelled= 330 miles

Time taken= 6 h

Lets find out speed of car drove.

Formula;
`Speed= (Distance)/(time)`

Speed=
`(330)/(6) = 55\ mph`

∴ Car´s speed is 55 mph.

As we have been informed that car´s rate of travel slows by 10 mph

∴ we have to reduce the current speed of car by 10 mph;
`(55-10)= 45\ mph`

The new slower rate of travel is 45 mph.