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A 12kg turtle rests on the bed of a zookeeper's truck, which is traveling down a country road at 55mi/h. The zookeeper spots a deer in the road, and slows to a stop in 12s. Assuming constant acceleration, what is the minimum coefficient of static friction between the turtle and truck bed surface that is needed to prevent the turtle from sliding?

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Answer:0.21

Step-by-step explanation:

Given

mass of turtle
m=12 kg

velocity of Truck
v=55 mi/h\approx 24.58 m/s

time taken to stop
t=12 s

using
v=u+at

where v=final velocity

u=initial velocity

a=acceleration

t=time


0=24.58+a\cdot 12


a=-(24.58)/(12)


a=-2.04 m/s^2

therefore 2.04 is the deceleration experienced by turtle which is countered by frictional force


a=\mu g ,where
\mu =coefficient of friction


2.04=\mu * 9.8


\mu =0.209\approx 0.21

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