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The degree of the function Fx) = -(x + 1)2(2x - 3)(x+ 2)? Is
1
, and its y-intercept is ( 0
,0
).

User Jage
by
5.3k points

1 Answer

4 votes

Answer:

Degree:3

Y-intercept:-6

Explanation:

The given function is:


f(x) = - {(x + 1)}^(2)( {2x - 3)}(x +2 )

To find the degree, we multiply out the leading terms of each factor.

The leading term of the first factor is:


- {x}^(2)

and that of the second factor is


2x

and the third one is:


x

If we multiply out the leading terms, we would get:


- {x}^(2) * 2x * x = - 2 {x}^(3)

Therefore the degree of the function is:

3

To find the y-intercept, we put x=0 to get:


f(0) = - {(0 + 1)}^(2)( {2 * 0 - 3)}(0 +2 )


\implies \: f(0) = ( 1)( - 3) * (2) = - 6

User Rimer
by
6.2k points
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