Question

Insert the values from the question above for x, y, z, & n into KxFey(C2O4)z·nH2O and provide the correct coefficients to balance the following equation: ___ Fe(NH4)2(SO4)2·6H2O + ___ H2C2O4 + ___ K2C2O4 + ___ H2O2 → ___ KxFey(C2O4)z·nH2O + ___ (NH4)2SO4 + ___ H2SO4 + ___ H2O

Answer 1

Answer : The balanced chemical reaction will be,

`2Fe(NH_4)_2(SO_4)_2.6H_2O+3H_2C_2O_4+3K_2C_2O_4+H_2O_2\rightarrow 2K_3Fe_1(C_2O_4)_3.3H_2O+2(NH_4)_2SO_4+2H_2SO_4+8H_2O`

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

`Fe(NH_4)_2(SO_4)_2.6H_2O+H_2C_2O_4+K_2C_2O_4+H_2O_2\rightarrow K_xFe_y(C_2O_4)_z.nH_2O+(NH_4)_2SO_4+H_2SO_4+H_2O`

This reaction is an unbalanced chemical reaction because in this reaction number of individual elements present on reactant side are not equal to the product side.

Thus, the balanced chemical reaction will be,

`2Fe(NH_4)_2(SO_4)_2.6H_2O+3H_2C_2O_4+3K_2C_2O_4+H_2O_2\rightarrow 2K_3Fe_1(C_2O_4)_3.3H_2O+2(NH_4)_2SO_4+2H_2SO_4+8H_2O`

By the stoichiometry we can sat that, 2 moles of
`Fe(NH_4)_2(SO_4)_2.6H_2O` react with 3 moles of
`H_2C_2O_4` and
`K_2C_2O_4` and 1 mole of
`H_2O_2` to give 2 moles of
`K_3Fe_1(C_2O_4)_3.3H_2O`, 2 moles of
`(NH_4)_2SO_4`, 2 moles of
`H_2SO_4` and 8 moles of
`H_2O`