Question

A force of 500.0 is represented graphically with its tail at the origin and the tip pointed in a direction 30.0° above the positive x-axis. What are the x- and y-components of the vector?

Answer 1

`F^(')=(250√(3),250 })`

Explanation:

We have F´ =500 and
`\alpha`=30º, so x and y components:

F´ =
`(F_(x) , F_(y))` this is

`F_(x) = F^(') *Cos\alpha`

`F_(y) = F^(') *Sin\alpha`

`F_(x) = F`*Cos\alpha =500*Cos30=500*(√(3) )/(2) =250√(3)`

`F_(y)=F*Sin\alpha  =500*Sin30=500*(1)/(2)=250`;

Finally

F' =
`(250√(3) , 250)`