Question

Write the expression 2a+b in the form of a fraction with a denominator of

1) 2a-b

2) 3a

PLEASE HELP ASAP

Answer 1

Part 1 =
`(4a^(2) -b^(2) )/(2a-b)`

Part 2 =
`(6a^(2) +3ab )/(3a)`

Explanation:

Let the fraction be denoted by numerator and denominator then given denominator for the first expression contains 2a-b.

let us assume that the numerator contains x

now given that 2a+b is the value of the expression which means

`2a+b=(x)/(2a-b)`

`x=4a^(2) -b^(2)`

Therefore the fraction for the first option is
`(4a^(2) -b^(2) )/(2a-b)`

Given the denominator for the second expression is 3a.

Let us assume that the numerator contains x

Now given that 2a+b is the value of the expression which means

`2a+b=(x)/(3a)`

`x=6a^(2) +3ab`

Therefore the fraction for the second option is
`(6a^(2) +3ab )/(3a)`